Calculate the set of unique abbreviations for a given set of strings.
require 'abbrev'
require 'pp'
pp Abbrev::abbrev(['ruby', 'rules']).sort
Generates:
[["rub", "ruby"],
["ruby", "ruby"],
["rul", "rules"],
["rule", "rules"],
["rules", "rules"]]
Also adds an abbrev
method to class Array
.
Given a set of strings, calculate the set of unambiguous abbreviations for those strings, and return a hash where the keys are all the possible abbreviations and the values are the full strings. Thus, given input of “car” and “cone”, the keys pointing to “car” would be “ca” and “car”, while those pointing to “cone” would be “co”, “con”, and “cone”.
The optional pattern
parameter is a pattern or a string. Only
those input strings matching the pattern, or begging the string, are
considered for inclusion in the output hash
# File ../ruby/lib/abbrev.rb, line 43 def abbrev(words, pattern = nil) table = {} seen = Hash.new(0) if pattern.is_a?(String) pattern = /^#{Regexp.quote(pattern)}/ # regard as a prefix end words.each do |word| next if (abbrev = word).empty? while (len = abbrev.rindex(/[\w\W]\z/)) > 0 abbrev = word[0,len] next if pattern && pattern !~ abbrev case seen[abbrev] += 1 when 1 table[abbrev] = word when 2 table.delete(abbrev) else break end end end words.each do |word| next if pattern && pattern !~ word table[word] = word end table end
Given a set of strings, calculate the set of unambiguous abbreviations for those strings, and return a hash where the keys are all the possible abbreviations and the values are the full strings. Thus, given input of “car” and “cone”, the keys pointing to “car” would be “ca” and “car”, while those pointing to “cone” would be “co”, “con”, and “cone”.
The optional pattern
parameter is a pattern or a string. Only
those input strings matching the pattern, or begging the string, are
considered for inclusion in the output hash
# File ../ruby/lib/abbrev.rb, line 43 def abbrev(words, pattern = nil) table = {} seen = Hash.new(0) if pattern.is_a?(String) pattern = /^#{Regexp.quote(pattern)}/ # regard as a prefix end words.each do |word| next if (abbrev = word).empty? while (len = abbrev.rindex(/[\w\W]\z/)) > 0 abbrev = word[0,len] next if pattern && pattern !~ abbrev case seen[abbrev] += 1 when 1 table[abbrev] = word when 2 table.delete(abbrev) else break end end end words.each do |word| next if pattern && pattern !~ word table[word] = word end table end